p^2+12p-28=0

Solution for p^2+12p-28=0 equation:

Simplifying
p2 + 12p + -28 = 0

Reorder the terms:
-28 + 12p + p2 = 0

Solving
-28 + 12p + p2 = 0

Solving for variable 'p'.

Factor a trinomial.
(-14 + -1p)(2 + -1p) = 0

Subproblem 1
Set the factor '(-14 + -1p)' equal to zero and attempt to solve:

Simplifying
-14 + -1p = 0

Solving
-14 + -1p = 0

Move all terms containing p to the left, all other terms to the right.

Add '14' to each side of the equation.
-14 + 14 + -1p = 0 + 14

Combine like terms: -14 + 14 = 0
0 + -1p = 0 + 14
-1p = 0 + 14

Combine like terms: 0 + 14 = 14
-1p = 14

Divide each side by '-1'.
p = -14

Simplifying
p = -14
Subproblem 2
Set the factor '(2 + -1p)' equal to zero and attempt to solve:

Simplifying
2 + -1p = 0

Solving
2 + -1p = 0

Move all terms containing p to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + -1p = 0 + -2

Combine like terms: 2 + -2 = 0
0 + -1p = 0 + -2
-1p = 0 + -2

Combine like terms: 0 + -2 = -2
-1p = -2

Divide each side by '-1'.
p = 2

Simplifying
p = 2
Solution
p = {-14, 2}